A car enters a tunnel at 24 m/s and accelerates steadily at 2.0 m/s2. At what speed does it leave the tunnel, 8.0 seconds later?

Given:

V1 = initial velocity = 24 m/s

a = acceleration = 2.0 m/s^2

s = time = 8 s

V2 = final velocity = ?

For linear-motion problems with those given terms, the following formula is used:

V2 = V1 + as

Substituting the given values:

V2 = 24 + 2 (8)

V2 = 24 + 16

V2 = 40 m/s

Therefore the car will have a speed of 40 m/s as it leaves the tunnel.