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30 August, 16:26

How long will it take a rock dropped from 2.0 m above the surface of mercury to reach the ground?

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  1. 30 August, 19:22
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    The answer is 1.04s.

    This is the example of free fall.

    Let's start with the kinematic formula:

    d = v1*t + 1/2a*t²

    where:

    d - distance

    v1 - initial distance (in free fall v1 = 0)

    t - time

    a - gravitational acceleration

    We have:

    d = 2m

    a = 3.7 m/s² (on mercury)

    t = ?

    In free fall, the expression looks like:

    d = 0*t + 1/2a*t² = 0 + 1/2a*t²

    ⇒ d = 1/2a*t²

    Now, from here t can be calculated:

    t² = d : 1/2a

    t² = 2d/a

    t = √ (2d/a)

    Let's replace the parameters:

    t = √ (2 * 2 / 3.7)

    t = √ (4/3.7)

    t = √1.08

    t = 1.04 s
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