Two balloons having the same charge of 1.2 * 10-6 coulombs each are kept 5.0 * 10-1 meters apart. What is the magnitude of the repulsive force between them? (k = 9.0 * 109 newton·meter2/coulombs2)

1.2 * 10-2 newtons

3.2 * 10-3 newtons

6.5 * 10-3 newtons

3.0 * 10-4 newtons

5.2 * 10-2 newtons

Steps: 1) dа ta: q1=charge of first balloon=1.2 * 10^-6 q2=charge of second balloon=1.2 * 10^-6 Condition:q1=q2 then for convenience, we say q instead of q1 and q2. Radius=r=5*10^-1 Radius is the distance between balloons! Magnitude of repulsive force=F=? 2) Solution: F=kq1q2/r^2 As q1=q2=q So F=kqq/r^2 = kq^2/r^2 Putting values: F = ((9*10^9) (1.2 * 10^-6) ^2) / (5*10^-1) ^2 Using calculator: F=0.05184 N