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4 April, 17:03

An object, initially at rest, is subject to an acceleration of 34 m/s^2. How long will it take for that object to reach 3400m?

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  1. 4 April, 20:44
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    Vf^2 = Vi^2 + 2ad

    a = 34 m/s^2

    Vi = 0 m/s

    d = 3400m

    Vf = 480.83 m/s

    a=v/t

    t=v/a

    t=480.83/34

    t=14.142 s
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