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19 October, 14:37

The number of molecules in a container is tripled and the kelvin temperature doubled. the volume remains unchanged. the new pressure will be how many times greater than the original pressure?

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  1. 19 October, 17:26
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    N2 = 3*n1

    T2 = 2*T1

    V1 = V2

    (n2 * T2) / P2 = (n1 * T1) / P1

    3 n1 * 2 T1 / P2 = n1 * T1 / P1

    P2 = 6*P1

    Since P2 is 6P1, it is 6 times greater than original pressure
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