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27 October, 00:10

A wooden box weighing 150 N is sliding at a constant rate over a concrete sidewalk. The force required to pull the box at a steady rate is 78 N. What is the coefficient of friction?

1.9

228

72

0.52

+2
Answers (1)
  1. 27 October, 01:11
    0
    78 also then equals the force of friction (steady rate, so sum of F = 0) Ffr = mu*Fn. Normal force = weight for this box = 150. mu = 78/150 = 0.52
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