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Today, 05:40

A freight train traveling with a velocity of - 4. o m/s begins backing into a train yard. if the train's average acceleration is - 0.27 m/s^2 what is the trains velocity after 17s

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  1. Today, 08:30
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    Suvat question!

    s = not needed

    u=-4

    v=?

    a=-0.27

    t=17

    we can used the equation:

    v=u+at

    v=-4 + (-0.27) (17)

    v=-4-4.59

    v=-8.59m/s
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