A 42 kg object goes from rest to 23 m/s, what is the magnitude of the force if it accelerates in. 67 seconds?

Force is equated as the product of mass and acceleration (F = ma). Since mass (m = 42kg) is already given, we only need to look for acceleration.

Acceleration can be obtained by dividing velocity by time. From that, we substitute the given values of t =.67s and v = 23m/s

a = v / t

a = (23m/s) /.67s

a = 34.33 m/s^2

Since we now have the value of a, we substitute it to the formula for force:

F = 42kg x 34.33 m/s^2

F = 1441.8 N

Force = mass x acceleration

we need 1st to get the acceleration

acc = velocity / time

acc = 23 / 0.67

acc = 34.33 m/s^2

by subs. in the first law

F = 34.33 * 42

Force = 1441.79 N