A car rolls along a surface with a coefficient of friction of. 795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?

Question

Physics

Adriel Duncan

22 August, 08:46

A car rolls along a surface with a coefficient of friction of. 795 I f the car has a mass of 905 kg, what force is needed to accelerate the car from rest to 102.5 km/hr in 10 sec?

+1

Answers (1)

Know the Answer?

Jonah Bean · Answer 1

102.5 km/hr = 28.5 m/s

a = (28.5 - 0) / 10

a = 2.85 m/s²

Resultant force = forward force - friction

ma = F - μmg

F = ma + μmg

F = 905 (2.85 + 0.795 x 9.81)

F = 9637.3 N

F = 9600 N