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22 February, 01:41

Work of 2 Joules is done in stretching a spring from its natural length to 19 cm beyond its natural length. What is the force (in Newtons) that holds the spring stretched at the same distance (19 cm) ?

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  1. 22 February, 03:03
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    Work done,

    Wd = 1/2*kx^2 2joules = 1/2*k * (0.19) ^2

    find k, spring constant Force that holds the spring stretched = k*0.19 N
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