At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational acceleration at a distance of 65 m from the center of the habitat? Be sure to show all work and steps to support your answer.

Question

Christina Singh

20 November, 09:29

+4

Answers (1)

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Matias Robertson · Answer 1

find the angular velocity by

w^2R = g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.2747 rad/s

and at R = 65:

a = w^2R = 0.2747^2*65 = 4.905 m/s^2 ( = g/2)