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1 July, 03:55

A student drops a ball from a window 3.5 m above the sidewalk. How fast is the ball moving when it hits the ground?

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  1. 1 July, 06:54
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    To answer this you must know that the acceleration caused by gravity upon the ball, or any object, is - 9.8 m/s^2

    there's two ways to solve this

    first, use the position equation

    x = (1/2) at^2+Vot+Xo

    Xo, the initial position, is 3.5 m

    x (t), the final position, is 0 m (the ground)

    Vo, the initial velocity, is 0 m/s, since you just drop the ball

    and a is - 9.8

    so

    0 = (1/2) (-9.8) t^2+3.5

    -3.5=-4.9t^2

    t^2=0.71

    t=0.845

    so it takes the ball 0.845 s to hit the ground

    now, using the velocity equation, v=at+Vo,

    v = (-9.8) (0.845) + 0=-8.28 m/s

    therefore, the speed of the ball is 8.28 m/s when it hits the ground
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