Ask Question
28 January, 01:48

Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms.

The bottle slides down the hill and is moving at a velocity of 14 meters/second the instant it hits the ground. The vertical height from where Jeff dropped the bottle is __?__ meters. Ignore friction, and use, PE = m * g * h, and g = 9.8 m/s2.

+5
Answers (1)
  1. 28 January, 03:10
    0
    The kinetic energy of the ball is

    KE = 1/2 (0.25) (14) ²

    KE = 24.5 J

    Equate it to the potential energy of the ball when it's dropped which is

    PE = 0.25 (9.81) h

    PE = 2.45 h

    Equating ...

    24.5 = 2.45 h

    Solve for h

    h = 10 m

    The bottle was dropped 10 m above the ground.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Jeff is part of a trekking team. As he climbs a hill, he drops his water bottle, which has a mass of 0.25 kilograms. The bottle slides down ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers