An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

Question

Physics

Alexandria Stuart

6 January, 22:20

An airplane touches down on the runway with a speed of 70 m/s2. Determine the airplane after each second of its deceleration.

+5

Answers (1)

Know the Answer?

Lillie Ruiz · Answer 1

vf^2 = vi^2 + 2*a*d

---

vf = velocity final

vi = velocity initial

a = acceleration

d = distance

---

since the airplane is decelerating to zero, vf = 0

---

0 = 55*55 + 2 * (-2.5) * d

d = (-55*55) / (2 * (-2.5))

d = 605 meters