Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in the Example above. If it strikes the ground 47.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.)

(a) the time of flight

s

The x coordinate as a function of time is x (t) = vcos (39.0) t, so the initial speed is v0 = Δx / (cos 39.0Δt), where Δx = 47.8 and Δt is the time of flight. Insert this into your equation for y (t) and solve for the time of flight.

Suppose the stone is thrown at an angle of 39.0° below the horizontal from the same building as in the Example above. If it strikes the ground 47.8 m away, find the following. (Hint: For part (a), use the equation for the x-displacement to eliminate v0t from the equation for the y-displacement.) (a) the time of flight sThe x coordinate as a function of time is x (t) = vcos (39.0) t, so the initial speed is v0 = Δx / (cos 39.0Δt), where Δx = 47.8 and Δt is the time of flight. Insert this into your equation for y (t) and solve for the time of flight. Note that the answer should be smaller than 3.16227766016838, since the stone is thrown down (and to the right). (b) the initial speed m/s (c) the speed and angle of the velocity vector with respect to the horizontal at impactspeed m/sangle °