Ask Question
28 April, 01:39

an object is shot straight upward from sea level with an initial velocity of 250 ft/sec.

a) assuming that gravity is the only force acting on the object, give an upper estimate for it's velocity after 5 seconds has elapsed. use g=32 ft/sec^2 for gravitational acceleration.

b) using delta t=1 sec, find a lower estimate for the height attained after 5 seconds ...?

+2
Answers (1)
  1. 28 April, 05:10
    0
    There are exact formulas for what you have asked for.

    a) V = V0 + g*t

    So V = 400 + - 32 * 5 = 400 - 160 = 340 ft/sec

    b) s = s0 + v0*t + (1/2) * g*t^2

    s = 0 + 400*5 - 16*25 = 2000 - 400 = 1600 ft

    You do not state in your problem how you are to estimate these.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “an object is shot straight upward from sea level with an initial velocity of 250 ft/sec. a) assuming that gravity is the only force acting ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers