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18 April, 15:32

a particle is constrained to move along a straight line through O.

it starts initially at D, which is a fixed distance from O in the positive direction& moves at a constant velocity of 4ms^-1 for 15 sec. until; it is 100m from O for a furhter 25 sec, after which it travels in the opposite direction for 20 sec.

the total distance is 180m.

How far from O does the particle stop?

how do i draw a velocity-time graph?

and what is the final displacement of the particle from its initial position? ... ?

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  1. 18 April, 16:44
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    x=1.9+2.5t+3.7 t2 V=2.5-3.7t V=0 when it stops 0=2.5-7.4t t=0.3378 a) x=1.9+2.5t+3.7 t2 (t=0.3378) x=3.1167m b) V=2.5-3.7t (t=0) V=2.5 but because it's returning here velocity is - 2.5
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