A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and the screen is located 3.14 m from the slits. the first bright fringe is located 3.32 mm from the center of the interference pattern. what is the wavelength of the laser light?

Question

Physics

Manatee

10 April, 08:35

A young's interference experiment is performed with blue-green laser light. the separation between the slits is 0.500 mm, and the screen is located 3.14 m from the slits. the first bright fringe is located 3.32 mm from the center of the interference pattern. what is the wavelength of the laser light?

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Brian Frost · Answer 1

Use the relation dsin (θ) = mλ

Your angle is given by θ=tan⁻¹ (3.32e-3/3.14) = 0.06058 degrees

λ = dsin (θ) / m = (0.5e-3) (0.001057) / 1 (use 1 in denominator since its the first order maximum)

λ = 5.2866e-7 Or λ = 528.66nm