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7 May, 19:48

The shoe is in contact with the initially nearly stationary 0.500 kg football for 20.0 ms. What average force is exerted on the football in Newtons to give it a velocity of 22 m/s?

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  1. 7 May, 22:13
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    If v=22m/s after0.02s then acceleration was

    22/0.02=1100m/s^2

    Now, F=ma = (0.5) (1100) = 550N
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