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12 May, 07:02

A motor running at 2600 rev/min is suddenly switched off and decelerates uniformly to rest after 10 s. Find the angular deceleration and the number of rotations to come to rest?

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  1. 12 May, 07:45
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    Angular acceleration = (change in angular speed) / (time for the change)

    change in angular speed = (zero - 2,600 RPM) = - 2,600 RPM

    time for the change = 10 sec

    Angular acceleration = - 2600 RPM / 10 sec = - 260 rev / min-sec

    (-260 rev/min-sec) x (1 min / 60 sec) = - (4 1/3) rev / sec²

    Since the acceleration is negative, the motor is slowing down.

    You might call that a 'deceleration' of (4 1/3) rev/sec².

    The average speed is 1/2 (2,600 + 0) = 1,300 rev/min = (21 2/3) rev/sec.

    Number of revs = (average speed) x (time) = (21 2/3) x (10sec) = (216 2/3) revs
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