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1 August, 05:11

In a simple electric circuit, the current in resistor is measured as (2.50+_0.05) mA. the resistor is marked as having a value of 4.7ohm+_2 %

if these values were used to calculate the power dissipated in the in the resistor. what would be the percentage uncertainty in the value.

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  1. 1 August, 09:05
    0
    Here is a hint for you

    P=VI=IR*I=I^2R
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