Ask Question
22 January, 02:07

Suppose a rocket ship in deep space moves with constant acceleration equal to 9.8 m/s2, which gives the illusion of normal gravity during the flight. (a) If it starts from rest, how long will it take to acquire a speed one-tenth that of light, which travels at 3.0 * 108 m/s? (b) How far will it travel in so doing?

+3
Answers (1)
  1. 22 January, 03:04
    0
    (a).

    It starts from rest, and its speed increases by 9.8 m/s every second.

    One tenth the speed of light is (1/10) (3 x 10⁸ m/s) = 3 x 10⁷ m/s.

    To reach that speed takes (3 x 10⁷ m/s) / (9.8 m/s²) = 3,061,224 seconds.

    That's about 35 days and 10 hours.

    (b).

    Distance traveled = (average speed) x (time of travel)

    Average speed = (1/2) of (1/10 the speed of light) = 1.5 x 10⁷ m/s.

    Time of travel is the answer to part (a) above.

    Distance traveled = (1.5 x 10⁷ m/s) x (3,061,224 sec) = 4.59 x 10¹³ meters

    That's 45.9 billion kilometers.

    That's 28.5 billion miles.

    That's about 6.2 times the farthest distance that Pluto ever gets from the Sun.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Suppose a rocket ship in deep space moves with constant acceleration equal to 9.8 m/s2, which gives the illusion of normal gravity during ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers