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28 January, 07:59

An object moving with uniform acceleration has a velocity of 14.0 cm/s in the positive x-direction when its x-coordinate is 2.85 cm. If its x-coordinate 3.15 s later is - 5.00 cm, what is its acceleration?

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  1. 28 January, 09:25
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    Though expressed in coordinate form, this is an example of linear motion. With the given, the acceleration can be solved using the following equation:

    s = Vo*t + (1/2) * a*t^2

    Where:

    s = displacement = 7.85 cm

    Vo = 14.0 cm/s

    t = 3.15 s

    a = ?

    Substituting:

    7.85 = (14) * (3.15) + (1/2) * a * (3.15) ^2

    a = - 7.31 cm / s^2
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