A baseball is thrown upward from a height of 2 meters with an intial velocity of 10 meters per second. determine its maximum height, using a (t) = - 9.8 meters per second as acceleration due to gravity.

The equation to be used for this would be as follows:

h (x) = - 9.8x^2 + 10x + 2

We need to find for the axis of symmetry for the time it takes to reach the maximum height and is expressed as:

x = - b / (2a)

x = - 10/2 (-9.8)

x = 0.51 seconds is the time it takes to reach the max. height

h (x) = - 9.8x^2 + 10x + 2

h (x) = - 9.8x0.51^2 + 10x0.51 + 2

h (x) = 4.55 m