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24 February, 07:54

A boy throws a stone horizontally from the top of a cliff of height h = 50.0 m towards the

ocean below. The stone strikes the water at a distance d = 60.0 m from the base of the cliff.

The time at which the stone lands in the water is 3.19s. Calculate the initial speed of the stone?

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Answers (1)
  1. 24 February, 09:32
    0
    The vertical component of the stone's initial velocity is 0 because it was projected horizontally.

    The horizontal component:

    velocity = displacement / time

    Vx = 60 / 3.19

    Vx = 18.8 m/s

    V = Vx

    So the stone's initial velocity is 18.8 m/s
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Home » Physics » A boy throws a stone horizontally from the top of a cliff of height h = 50.0 m towards the ocean below. The stone strikes the water at a distance d = 60.0 m from the base of the cliff. The time at which the stone lands in the water is 3.19s.
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