Two forces F1 and F2 act on a 5.00 kg object. Taking F1=20.0N and F2=15.00N, find the acceleration of the object for the configurations:

a) mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction

b) mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal.

A) mass m with F1 acting in the positive x direction and F2 acting perpendicular in the positive y direction

m = 5.00 kg

F1=20.0N ... x direction

F2=15.00N ... y direction

Net force ^2 = F1^2 + F2^2 = (20N) ^2 + (15n) ^2 = 625N^2 = >

Net force = √625 = 25N

F = m*a = > a = F/m = 25.0 N / 5.00 kg = 5 m/s^2

Answer: 5.00 m/s^2

b) mass m with F1 acting in the positive x direction and F2 acting on the object at 60 degrees above the horizontal.

m = 5.00 kg

F1=20.0N ... x direction

F2=15.00N ... 60 degress above x direction

Components of F2

F2, x = F2*cos (60) = 15N / 2 = 7.5N

F2, y = F2*sin (60) = 15N * 0.866 = 12.99 N ≈ 13 N

Total force in x = F1 + F2, x = 20.0 N + 7.5 N = 27.5 N

Total force in y = F2, y = 13.0 N

Net force^2 = (27.5N) ^2 + (13.0N) ^2 = 925.25 N^2 = Net force = √ (925.25N^2) =

= 30.42N

a = F / m = 30.42 N / 5.00 kg = 6.08 m/s^2

Answer: 6.08 m/s^2