A rocket is launched from ground level with an initial vertical velocity (v0) of 176 ft/s. After how many seconds will the rocket hit the ground? (Hint: h (t) = - 16t2 + v0t + h0).

explain.

We know that v0 is 176 ft/s and h0 is 0 because the rocket is at ground level before launch.

h (t) will also equal 0 when the ground hits the ground. We substitute these values:

0 = - 16t² + 176t

Solving the equation,

t = 0; t = 11 seconds

The rocket starts from the ground, t = 0, and comes back to the ground at t = 11 seconds.