A research submarine has a 30-cm-diameter window that is 8.6 cm thick. The manufacturer says the window can withstand forces up to 1.2*106 N.

What is the submarine's maximum safe depth in sea water? The pressure inside the submarine is maintained at 1.0 atm.

Express your answer using two significant figures.

First solve the area of the ow the window os the submarine

A = pi * (0.15) ^2 = 0.0707 m2

The pressure it can with stand is

P = F/A = 1.2x10^6 N / 0.0707 m2 = 16976527.26 Pa

Using the formala

P = pgh

Where p is the density of water

G is the accelartion due to gravity

H is the depth

H = P/pg

=16976527.26 Pa / (1000 kg/m3) (9.81 m/s2)

H = 1730.53 m