On a distant planet, a rock falls in 48.4 s from the top of a 1.10e+02 m cliff to the planet surface below. What is the acceleration due to gravity on this planet? m/s2 What is the final velocity of the rock just before it hits the planet's surface? m/s

this can be solve using the formala of free fall

t = sqrt (2y / g)

where t is the time of fall

y is the height

g is the acceleration due to gravity

48.4 s = sqrt (2 (1.10e+02 m) / g)

G = 0.0930 m/s2

The velocity at impact

V = sqrt (2gy)

= sqrt (2 (0.0930 m/s2) (1.10e+02 m)

V = 4.523 m/s