What is the gravitational force acting on a 70.0 kg object standing on the earth's surface?

G (gravitational acceleration) = - 9.81 m/s^2

m (mass) = 70.0 kg

According to Newton's second law of motion:

"F=ma"

Force is equal mass per acceleration therefore

W=mg

This is because weigth is the force of gravity acting in a body and "a" is replaced by "g" because "g"

is gravitational acceleration

Therefore:

W = mg

W = (70.0 kg) (-9.81m/s^2)

W = - 686.7 N

* The "N" means newton which is (kg * m/s^2)