A transformer has a primary coil with 600 turns and a secondary coild of 300 turns, if the output voltage is 320 volts, what is the input voltage?

We can calculate this problem using this formula: N (p) / N (s) = V (p) / V (s).

Where in the given values are:

N (p) = 600

N (s) = 300

V (s) = 320

V (p) = ?

So;

N (p) / N (s) = V (p) / V (s)

600 / 300 = x / 320 V

192,000 = 300 x

640 = x

This will give us a value of 640 V, which is the input input voltage.