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28 April, 11:20

A sailor pulls a boat horizontally alongside a dock for 10.0m with a rope angled at 40.0 degrees. He does 766 jules of work. What force did he apply to pull the boat?

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  1. 28 April, 13:00
    0
    For work we use the Formula: W = F. d. cosΘ.

    W = 766 J

    d = 10m

    Θ = 40

    766 = F. 10. Cos (40)

    F = 766/6.669

    F=116.35N

    This is what I'm getting the amount of Force used can not be so close to the value of work done.
  2. 28 April, 14:33
    0
    Work is equal to force times the distance. However, the distance here is angled horizontally alongside a dock. And so, we have distance times the cos (theta). The equation is W = Fdcos (theta).

    W = Fdcos (theta)

    766 J = F (10m) cos (10degrees)

    F = 77.78 N
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