A machinist turns the power on to a grinding wheel, at rest at tome t=0 s. the wheel accelerates uniformly for 10 s and reaches the operating angular velocity of 58 rad/s. the wheel is run at the angular velocity for 30 s and then a brake is applied which immediately stops the wheel. how many revolutions does the wheel undergo from t=0 until is stops?

Question

Jonas Sampson

30 July, 18:03

+3

Answers (1)

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Roger Orozco · Answer 1

To convert 2030 rad into rev, divide 2030 by 2pie. So final answer will be 2030/2 pie = 323.08 revolutions.