4786 joules fer transferred to an 89.0 gram sample of a unknown material with an initial temperature of 23.0°C what is the specific heat of the measure in the final temperature is 89.5°C

Specific heat formula is Q=M*C*ΔT

Q is amount of energy (4786 J)

M is mass (89.0 g)

C is specific heat (unknown, answer will be in J/gºC)

ΔT is the change in temp (89.5-23.0=66.5ºC)

Let's plug it in.

4786=89.0 (C) (66.5)

4786=5918.5 (C)

/5918.5

C=.8086508406 J/gºC

with sig figs ...

C=.809 J/gºC