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30 October, 06:13

If you drop a stone from height of 2.5m. what is the speed of the stone right before it hits the ground?

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  1. 30 October, 09:21
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    Since the stone was dropped from height, its initial velocity = 0 m/s

    Using v² = u² + 2gs.

    Where g ≈ 10 m/s², u = initial velocity = 0 m/s, s = height from drop = 2.5 m

    v² = u² + 2gs

    v² = 0² + 2*10*2.5

    v² = 0 + 50

    v² = 50

    v = √50

    v ≈ 7.07 m/s

    Hence velocity just before hitting the ground is ≈ 7.07 m/s
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