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3 December, 03:51

If the velocity of a car is halved the fc required to keeo it in a path of constant radius is multiplied/divided by?

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Answers (2)
  1. 3 December, 04:32
    0
    It should be the 4 ... so the answer is 4 ...
  2. 3 December, 05:24
    0
    I believe this is it

    The centripetal force is given by

    F = mv^2 / r

    When v' = v/2,

    F' = mv'^2/r = m (v/2) ^2/r = mv^2/4r = F/4.

    So the centripetal force is divided by 4.
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