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28 April, 18:36

A 40 kg skier starts at the top of a 12-meter high slope at the bottom she is traveling 10 m/s how much energy does she lose friction?

A. she doesn't lose any because mechanical energy is always conserved

B. 4,704 J

C. 2,000 J

D. 2,704 J

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Answers (1)
  1. 28 April, 18:56
    0
    Potential energy at top:

    PE = mgh

    PE = 40 x 9.81 x 12

    P. E = 4,708.8 J

    Kinetic energy at bottom:

    KE = 1/2 mv²

    KE = 1/2 x 40 x 10²

    K. E = 2,000 J

    P. E = K. E + Frictional losses

    Frictional losses = 4708 - 2000

    Frictional losses = 2708 J

    The answer is D.
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