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3 May, 15:48

Tarzan, in one tree, sights Jane in another tree

He grabs the end of a vine with length 20 m that makes an angle of 45 degrees with the vertical, steps off his tree limb, and swings down and then up to Jane's open arms

When he arrives, his vine makes an angle of 30 degrees with the vertical

Determine whether he gives her a tender embrace or knocks her off her limb by calculating Tarzan's speed just before he reaches Jane

Ignore air resistance and the mass of the vine.

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  1. 3 May, 17:22
    0
    Taking the distance of Tarzan from the ground before and after he makes the swing:

    Ho (initial height) = L (1 - cos45) = 20 (1 - 0.707) = 5.86 meters

    Hf (final height) = L (1 - cos30) = 20 (1 - 0.866) = 2.68 meters

    Difference in height = 5.86 - 2.68 = 3.18 meters

    PE = KE

    mgh = (1/2) mv^2

    Solving for v:

    v = sqrt (2*g*h)

    v = sqrt (2*9.8*3.18)

    v = 7.89 m/s

    With Tarzan going that fast, it is likely that he will knock Jane off.
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