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22 May, 14:25

A 72-kg fisherman in a 114-kg boat throws a package of mass m = 15 kg horizontally toward the right with a speed of vi = 5.0 m/s. Neglecting water resistance, and assuming the boat is at rest before the package is thrown, find the velocity of the boat after the package is thrown.

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  1. 22 May, 16:51
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    We are going to use law of conservation of Momentum.

    Momentum of package thrown = Momentum of the man and the ship

    Mass of Package * Velocity of Package = Mass of man and ship * velocity of both.

    15*5 = (72 + 114) * v

    75 = 186*v

    186v = 75

    v = 75/186

    v ≈ 0.403 m/s

    The velocity of the boat and the man after the package is thrown is ≈ 0.403 m/s toward the left.
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