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11 September, 00:24

Un fir, de sectiune S = 5 mm patrati si lungime L0 = 32 cm, este intins de o forta. Stiind ca E = 3 * 10 la put 7 N/m patrat, sa se calculeze constanta elastica k a firului.

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  1. 11 September, 02:35
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    Delta l=F*l0/S*1. E

    F=S*E*delta l/l0

    Fe=k*delta l

    F=Fe=>S*E*delta l/l0=k*delta l

    #Cuplacerecolegu = )))
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