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24 January, 05:20

A concrete cube of side 0.50 m and uniform density 2.0 x 103 kg m-3 is lifted 3.0 m vertically by a crane. what is the change in potential energy of the cube

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  1. 24 January, 08:40
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    Potential Energy = mgh

    But Mass = Density / volume, Volume of cube = (0.5*0.5*0.5) m³

    Mass = (2 * 10³) / (0.5*0.5*0.5) = 16 000 kg

    Potential Energy = mgh, g ≈ 10 m/s² h = 3.0 m

    Potential Energy = 16000*10*3 = 480 000 Joules
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