A concrete cube of side 0.50 m and uniform density 2.0 x 103 kg m-3 is lifted 3.0 m vertically by a crane. what is the change in potential energy of the cube

Potential Energy = mgh

But Mass = Density / volume, Volume of cube = (0.5*0.5*0.5) m³

Mass = (2 * 10³) / (0.5*0.5*0.5) = 16 000 kg

Potential Energy = mgh, g ≈ 10 m/s² h = 3.0 m

Potential Energy = 16000*10*3 = 480 000 Joules