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13 February, 09:32

An elevator is moving upward at 1.20 m/s when it experiences an acceleration of 0.31 downward over a distance of 0.75m. What will its final velocity be?

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  1. 13 February, 12:21
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    Info.: Vi = 1.20 m/s, a = 0.31 m/s^2, Δx = 0.75 m, Vf = ?

    Vf = sqrt (Vi^2 + 2aΔx) = sqrt ((1.20 m/s) ^2 + 2 (0.31 m/s^2 * 0.75 m))

    = 0.99 m/s
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