The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by the expression v = (-5.15 multiplied by 107) t2 + (2.30 multiplied by 105) t, where v is in meters per second and t is in seconds. The acceleration of the bullet just as it leaves the barrel is zero.
(b) Determine the length of time the bullet is accelerated.
(c) Find the speed at which the bullet leaves the barrel.
(d) What is the length of the barrel?
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Home » Physics » The speed of a bullet as it travels down the barrel of a rifle toward the opening is given by the expression v = (-5.15 multiplied by 107) t2 + (2.30 multiplied by 105) t, where v is in meters per second and t is in seconds.