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2 November, 19:04

A particular frost-free refrigerator uses about 710kWh of electrical energy per year. Express this amount of energy in J, kJ, & Cal.

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  1. 2 November, 21:53
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    A particular frost-free refrigerator uses about 710kWh of electrical energy per year. You are to express this amount of energy in J, kJ, & Calories.

    1 year (365 days / 1 year) (24 hours / 1 day) (3600s / 1h) = 31,536,000s

    710 kWh/yr (1 yr) = 710 kWh

    710 x 10^3 Wh = 710 x 10^3 (J/s) (31,536,000s) = 2.24 x 10^13 J

    2.24 x 10^13 J = 2.24 x 10^10 kJ = 5.35 x 10^12 cal
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