A ball has an electric charge of + 1.5 * 10-9 coulombs. At what distance from the ball's center is the electric field strength equal to 5.8 * 105 newtons/coulomb?

F = kq1q2/r 2

Where,

F - Coulomb Force

k - constant value which is equal to 8.98 * 10^9 newton square metre per square coulomb

q1 and q2 - two electric charges

r - distance.

5.8 * 10^5 = 1.5 * 10^-9 / r^2

5.8 * 10^5 r^2 = 1.5*10^-9

r^2 = 0.0000258620

r = 0.0050854694

So the distance is equal to 5.09 x 10^-3