An airplane starts from rest and reaches a takeoff velocity of 60.0m/s due north in 4.0s. How far has it traveled before take off?

Initial velocity, u = 0

Final velocity, v = 60 m/s (at take off)

Duration of the acceleration, t = 4 s

Calculate average acceleration.

a = (v - u) / t

= (60 m/s) / (4 s)

= 15 m/s²

Calculate the distance traveled during acceleration.

s = ut + (1/2) * a*t²

= 0.5 * (15 m/s²) * (4 s) ²

= 120 m

Answer: 120 m