What is the mass (in grams) of 9.66*10 to the 24 molecules on methanol (CH3OH)

First, determine the amount of methanol in moles by dividing the given number of molecules by the Avogadro's number.

(9.66 x 10^24 molecules) / (6.022 x 10^23 molecules / mol) = 16.04 moles

Multiply this number of moles to the molar weight of methanol which is equal to 32 g/mol

(16.04 moles) x (32 g/mol) = 513.28 grams

Therefore, the mass of methanol is approximately equal to 513.28 grams.