Consider a particle with initial velocity v⃗ that has magnitude 12.0 m/s and is directed 60.0 degrees above the negative x axis. What is the x component v⃗ x of v⃗? What is the y component v⃗ y of v⃗?

We are given with the data that the angle of velocity is above the negative axis. hence, the angle lies in the second quadrant with negative x axis and positive y axis. In this case, the x component is - 12 cos 60 equal to - 6 m/s while the y-component is 12 sin 60 equal to 6 sqrt of 3 m/s.