Ask Question
17 August, 15:49

A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed.

b) How many revolutions does it make in 15 s if it starts at rest?

I found the angular acceleration, 2 rad/s^2, but I don't know how to find the amount of revolutions.

+3
Answers (1)
  1. 17 August, 17:42
    0
    You have to find the calculate the circumference first then you can just multiply the diameter by π, which is about 3.142. That gives you the distance for each revolution. Then you can multiply by the number of revolutions per minute.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “A torque of 50 N*m acts on a wheel of moment of inertia 25 kg*m^2 for 4 s and then is removed. b) How many revolutions does it make in 15 s ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers