Ask Question
10 November, 15:10

Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the horizontal. What is the height of the building?

+5
Answers (1)
  1. 10 November, 18:55
    0
    Since his line of sight 63 degrees makes with the tip of the building

    Tan63° = height of building / Horizontal distance

    tan63° = Height / 50

    50tan63° = Height

    Height = 50tan63°

    Height ≈ 50*1.9626

    Height ≈ 98.13 m

    Height of the building is ≈ 98.13 m. Mind you in solving for this height we have neglected the height of Daniel.

    The height of building actually should be 98.13 m plus the height of Daniel. Since the 63° was measured from his eye level.
Know the Answer?
Not Sure About the Answer?
Find an answer to your question ✅ “Daniel is 50.0 meters away from a building. He observes that his line-of-sight to the tip of the building makes an angle of 63.0° with the ...” in 📘 Physics if you're in doubt about the correctness of the answers or there's no answer, then try to use the smart search and find answers to the similar questions.
Search for Other Answers